Example 1 · difficulty 4/5
A parallel plate capacitor with plate separation d has capacitance C₀ in air. A slab of thickness d/2 and dielectric constant 4 is inserted between the plates, filling half the gap. The new capacitance is:
- A. 2.5 times C₀
- B. 1.6 times C₀
- C. 4 times C₀
- D. equal to C₀